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15x^2-60x-900=0
a = 15; b = -60; c = -900;
Δ = b2-4ac
Δ = -602-4·15·(-900)
Δ = 57600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{57600}=240$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-240}{2*15}=\frac{-180}{30} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+240}{2*15}=\frac{300}{30} =10 $
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